The cargo machine at speed is approaching the intersection. Errors associated with the assessment of the current road situation. Code of the Russian Federation on administrative offenses

The driver, driving the adjustable intersection of roads, is enough to perform the orders of the traffic light or an employee of the traffic police. In principle, it is quite simple. Move on an unregulated intersection is much more complicated.

What is such a junction

Approaching the intersection of roads, attention should be paid, the order of the passage of transport. Adjustable and unregulated intersections have one main difference - the presence of either the absence of a traffic light and a controller. The presence of the latter says about and the absence indicates that you are, on the contrary, on an unregulated crossing of roads.

Signs

Road signs will help a person driving a vehicle to understand what crossing the passage of the frequencies in front of him and how to do it. So, on an unregulated crossroads are established - "give way to the road", " the main road"," Motorway "," End of the motorway "," Intersection with a secondary road "," Incoming the secondary road "and others.

You can drive it right and without road accidents you can only know how to read signs.

Travel unregulated intersections: Rules

Before starting to move on an unregulated intersection, it is necessary to learn everything set signs. And then, taking them into account, start moving, given the rules. An unregulated intersection will not cause you difficulties if you know how to read signs and remember traffic rules.

Fireless vehicles do not have advantage over tram, regardless of the direction of movement and the status of the roadway on which there are. Therefore, cars always miss them, and only after that begin traffic according to the established road signs.

Before crossing the road there is a sign "Main Road"

As repeatedly mentioned, the movement in unregulated intersections depends on the established signs. Therefore, in order to correctly drive an unregulated road crossing, you should know who needs to be skipped, and where you have an advantage. There are several options for the passage of the unregulated intersection.

It all depends on how the main road is located and your location relative to it.

1. If the vehicle is located on the main route and it continues directly, then the algorithm of movement of your car is as follows:

• If you wish, to drive in the forward direction - no one should give up the road.
• Planning to turn right - you also have the advantage. Accordingly, the intersection is passing first.
• Turn to the left - first of all skip the counter cars, which, as well as you, are on the main road. Namely, you should get closer to the middle of the intersection, wait until they go out, and only after that continue to move. In the event that the oncoming vehicles turn to the left, you simultaneously run around the right parties of cars.
• If you are going to turn around, then the sequence of actions is the same as when turned to the left.

2. The main road turns right. Your actions:

• When moving, right remember about the interference on the right. If there is a car, then skip it, and then start passing the crossroads.
• Rotate right is the only direction in which you have an advantage. Therefore, it is possible to boldly roll, not inferior to anyone.
• When turning left, you skip cars that are located on the right and move directly or left. If your plans to turn right, then you are allowed to move at the same time, since in this situation you do not interfere with its movement.
• Turn. In this situation, the same rules are working as when turning to the left.

3. The main road turns to the left. Your actions:

• If you wish to move directly with your priority, so you drive first.
• When turning to the right you have an advantage, therefore, not inferior to anyone, perform maneuver.
• Turning left occurs on the same algorithm as to the right.
• When reversing should be given to vehicles moving on the left, according to traffic rules. The unregulated intersection they, as well as you, pass along the main road, and the advantage of them is formed due to the fact that they are no interference to you.

Before crossing the roads, a sign "Give the road"

According to traffic rules, if on your road is installed a sign "LEAGE ROAD", you first miss cars moving along the main road, and then those who are a hindrance to you right.

Stop at the intersection of roads:

• Before you is the sign "Give the road". If you wish, turn right you misses your interference to the right (even if it takes a turn), also skip the car to the left due to the fact that it is heading along the main road. However, if he turns to the right, you are allowed to start moving simultaneously with it. When driving, it is directly an advantage in front of you to the right and left, so you give way to the roadway. When you turn left you misses everyone. The same when performing reversal.
• The main road is located on the right of you. When turning to the right it has the priority of the counter car. Also a straight vehicle on the right in case of reversal. You also miss them if you plan to continue moving directly and roll left. Before the reversal, you will have to give all cars from three directions.
• The main road is to the left of your TC. Before turning to the right you are obliged to cede the ones and on the left of cars, because they are on the main road, respectively, have an advantage. By skipping cars on the main roadway (left, from the oncoming direction) and on the right (to the right of the right), you have the opportunity to cross the unregulated intersection towards directly. You also have no advantage when turning to the left.
• The reversal at such an intersection is better not to perform, but if there is no other option, then start the maneuver is allowed only by passing vehicles from three directions.

Travel unregulated equivalent roads

In a situation where you have to get an intersection of equivalent roads, the main rule that you must be guided is to interfere on the right.

Who should miss, depends on where you are going. You are planning:

• Turn right. In this situation, you should not give up anyone, as the advantage of you, respectively, your car is passing first.
• Go straight. If the vehicle is on the right, it means that you miss it, and then drive yourself. Sometimes it turns out that at the same time from four directions, cars plan to cross the unregulated intersection of equivalent roads directly. PDDs do not regulate this situation, so drivers must determine each other, which of them will begin to move first.
• Turn left. In these circumstances, the opposite and found right side car. Based on this, you start moving only after them.
• Make a turn. To start this maneuver, you must skip the vehicle from three directions, and only after that start moving.

Pedestrian and unregulated intersection

Since regulation is missing at the intersection, then in situations with the suppression of the intersection, you need to be very attentive. After all, in case of an accident, the maximum will be paid a fine, and for you as a driver, this situation can turn into deprivation of rights and even in prison.

Pedestrian at an unregulated intersection, moving along Zebra, has an advantage over any vehicle. If a person decided to cross the roadway on which there is no crosswalkYou do not have to skip it. But, as practice shows, faster and easier to give way to a negligible pedestrian.

Summarizing the rules controlling the passage of unregulated intersections can be distinguished by three main items that need to follow:

• Interference to the right at the intersection of equivalent roads. Be sure to keep track of whether there are vehicles to the right of you.
• With the sign of the "LDA way", the driver initially draws attention to the one who goes along the main road, then on moving on the right.
• If on the road you move is the "Main Road" sign, then you closely watch those who are also heading along the main road and to the right of you.

Crossroads is the place of intersection, adjoining or branching roads at one level.

In other words, two or several roads, intersecting in one place, form one intersection. Crossing roads at different levels (overpass, overpass, bridges, etc.) are not considered intersections.

Perekrestok

Also do not form crossroads from the road from the surrounding territories.

General rules for crossroads

The order of movement through the intersection depends on what type it refers. However, I. general ruleswhich act on any intersections.

These are these rules:

1. Turning at the crossroads to the right or left, the driver is obliged to miss pedestrians walking through that road to which he turns, as well as cyclists, continuing the movement in the direct direction along the bike path or along the edge of the carriageway. The exception is cases where pedestrian movement is regulated by a separate traffic light. If during the rotation of the vehicle pedestrians, a prohibitive signal is burning, then the road should not be redesed.
2. It is forbidden to enter the intersection, if it fell on it or behind it, which will force the driver to stop at the intersection of passages, creating an obstacle to the movement of other vehicles in the transverse direction. In this case, you can enter the intersection only to immediately leave it in a free direction (for example, by performing a turn or turn). If you need to move precisely in the direction in which the plum was formed, then it is necessary to stop before entering the intersection of the passage parts and resume movement only after a free space for your vehicle appears behind the intersection.
3. At any intersections of the vehicle with included flashing beacons blue (blue and red) color and special sound signal (Sirena) have an advantage regardless of the road signs available at the crossroads, markup, as well as traffic lights. The rest of the drivers are obliged to give way to a special vehicle and those whom it accompanies.

Algorithm for travel Perekrestkov

The location algorithm of any intersection consists of three actions:

• First, you need to correctly navigate and even before entering the intersection, determine what kind of applies.
• Secondly, applying the relevant rules, you need to give way to those who have an advantage, after which it is in time to drive into the intersection.
• Thirdly, after entering the intersection, you need to leave it in a timely manner in the desired direction. At this stage, it may also be necessary to give way to other drivers and pedestrians.

Views of Perekrestkov

Crossroads can have a different configuration. They are cruciform, T-shaped, in the form of a star, triangle, etc.

There are crossroads with circular motion and transport junctions, on which instead of one large crossroads are made several small.

However, the rules for the passage of crossroads depend not on their shape and size, but what kind of crossroads include one or another intersection.

Adjustable intersection - This is such an intersection, where the sequence of motion is determined by the signals of the acting traffic light or the controller.

If the traffic light and the controller are missing, then the intersection is considered unregulated, and drivers define the priority of travel on their own, on those rules that act in unregulated intersections.

Also considered unregulated intersection, on which:

• traffic light is available, but does not work;
• traffic light is available, but works in a flashing yellow signal mode;
• the adjustor is present, but does not give drivers and pedestrians regulating motion.

It's important to know!
In cases where the traffic controller controls, drivers and pedestrians must fulfill its requirements, even if they contradict traffic lights, priority signs, as well as other road signs and markup.

Unregulated intersections are divided into equivalent and unequivocal. At an unequal intersection there is always the main road, and the rest of the roads are secondary to her.

Naturally, the one who moves along the main road has an advantage over those who are in the secondary road.

You should be able to independently find the main and minor roads at an unequal intersection.

If you do not have time to do this while you approach the intersection, you will not be able to correctly determine who has an advantage, and who should give way to the road. Without following the priority of travel, you can make a serious accident.

the main road

Three signs of the main road:

1. The motorway marked with 5.1 is always the main thing in relation to all other roads that adjoin it.
2. The road with a solid coating (asphalt, concrete, crushed stone, blocking and the like) is always the main one in relation to intersectable or adjacent dirt road, provided that there are no priority signs and a sign 1.6 at the intersection.
3. The road marked in front of the intersection signs of priority 2.1, and outside settlements - Also signs 2.3.1- 2.3.7 (2.3.1, 2.3.2, 2.3.3, 2.3.4, 2.3.6, 2.3.5, 2.3.7, is always the main one in relation to intersectable or adjoining road. The road that is indicated by signs 2.4 or 2.5 is always secondary. Signs 2.1, 2.4 and 2.5 are installed immediately before the intersection, and 2.3.1 - 2.3.7 at a distance of 150 - 300 meters to it.

At some intersections, the main road can rotate left or right. In this case, the priority signs are set with signs 8.13 "Direction of the main road": sign 2.1 - with a sign 8.13, and signs 2.4 or 2.5 - with a plate 8.13.

The main road is shown on these tablets with a thick line, and the minor roads are thin. If signs 2.1, 2.4 or 2.5 are installed without plates 8.13, then you can be sure that neither the main nor the secondary road at this intersection changes directions.

If the driver cannot determine the presence of a coating on the road (the dark time of day, dirt, snow, etc.), and there are no priority signs at the crossroad, then in order to security items, it should be considered in the secondary road.

It's important to know!
Priority marks are installed on adjustable intersections, but in this case the drivers should not submit to them, but exclusively signals of the traffic light or a controller. If the traffic light fails or turns out to be turned off, the intersection will become unregulated, and only then the priority marks will take effect. Thus, approaching the intersection, the driver must first of all pay attention to the presence of a traffic light (adjustment), and only if it is not - to look for the priority signs in the field of view.

There are no main and secondary roads on an equivalent intersection - all intersecting roads are equal in their meaning. As a rule, there is no intensive movement at such intersections, therefore it makes no sense to install traffic lights and priority marks.

Their absence and is a sign of equivalent crossroads. In some cases, but not always, a warning sign 1.6 can be installed before the equivalent intersection.

For equivalent crossroads, there are regulations that differ from the rules acting on regulated and uneven intersections.

Travel unregulated crossies

The rules set the order of the passage of the unregulated intersection depending on the type of crossroads, the relative position of the vehicle or pedestrians, as well as on the directions of their further movement.

At the same time, some participants of the movement must give way to others.

However, if you know exactly that your path at the intersection will not intersect with the trajectory of another vehicle (for example, when moving towards each other in the forward direction), then with such a vehicle you can move through the intersection at the same time.

Directions of unregulated intersections of equivalent roads

At the equivalent intersection, all roads adjacent to it are equal to the value. However, this does not mean that all participants in the movement are in equal conditions.

At such a crossroads there are two queues: the first is for trams, and the second is for fire-free vehicles.

When there are several trams and germ vehicles on the equivalent crossroad, the paths of which are intersecting, drivers are guided inside each of these two queues when entering the intersection by us to interfere with the right, according to which such an interference needs to give way to the road.

According to this rule, trams are driving around with each other, and the fireless vehicles are with each other, after the trams erupt.

Liting the road to trams and to the right of you without a fine vehicles, you get the right to enter the equivalent crossroads.

However, in some cases, it is not possible to leave him immediately.

Before leaving in the right direction, you need:

• when turning to the right - to give way to pedestrians and cyclists that crossed the road to the right of you;
• when turning to the left - to give the road to the counter TC, moving directly and right (that is, there, wherever you want to turn and you), as well as pedestrians, passing the way to the left of you;
• with a turn - oncoming vehicles and those who approach the crossroads on the left side (in the process of reversal, such TCs will also be counter for you);
• when moving, it is possible to directly leave the crossroads freely if you entered it correctly on it;
• turning to the left of two vehicles moving from counter directions can be performed simultaneously provided that both drivers choose non-intersecting trajectories and maintain a safe side interval. At the same time, the crossing at the intersection is carried out with right side. Performing such a travel, you need to be taken care, since the oncoming vehicle rotating to the left can heat the car or a motorcycle riding in the forward direction.

The equivalent crossroads are distinguished by the low intensity of the movement, so the situation is when the fireless TCs arrived at the same time from four sides and created each other's interference to the right, it arises very rarely.

The rules such a situation do not regulate, therefore, drivers should determine the order of movement by agreement. After one of the four TCs, first of all, the remaining three driver will be able to disperse on the rule of interference on the right.

Travel of unregulated intersections of the main and secondary roads

If there is a main road at an unregulated intersection, vehicles moving along it have an advantage over those who move on a secondary road.

It does not matter on what road your TC will be after the location of the crossroads - the sequence of motion is determined by what way you drove up to it.

So, the driver turning from the main road to the secondary, still has an advantage over the driver who turns from the secondary road to the main thing.

It's important to know!
In any case, the driver who is in the secondary road does not have the right to enter the intersection until the main road is free from all vehicles, which are either already at the crossroads or approach it.

If there is a tram movement on the main or secondary road, the entrance to the crossroads is carried out in four queues:

• the first is the trams that took place on the main road;
• the second stage constitutes firefight vehicles that arrived along the main road;
• third place constitutes trams that approached the secondary road;
• the fourth turn is the fireless vehicles that arrived at the secondary road.

Thus, your turn may turn out to be the second or fourth in such an intersection - depending on what road you arrived.

If the main road at the intersection turns, then a situation is possible when the trajectories of vehicles, found by the main road, intersect with each other.

The same situation is possible between the CU, which are in secondary roads.

In this case, the drivers who were in equal terms, that is, on the same road, should be guided by the rule of the opposite to the right.

Drivers located on secondary roads travel around, guided by this rule, after both directions of the main road are fully released.

Departure from an unequal intersection is carried out according to the same rules as departing from the intersection of equivalent roads. When turning to the left or right, you need to give way to pedestrians and cyclists.

If the main road does not turn, then when turning to the left and turn, you will have to skip the counter vehicles. At the intersections with the turn of the main road, leaving the left does not represent complexity, and the turn should be carried out as shown in the figure.

Circular motion crossroads

The passage of the crossroads with a circular motion is carried out according to the same rules that act at the rest of the intersections.

In the absence of priority marks, the crossroads is equivalent, and drivers are guided by the rule of interference to the right. If there are signs "give way to the road" drivers entering the intersection, give way to those who are already moving in a circle.

Travel adjustable Perekrestkov

On adjustable intersections, the mode of movement is determined by the signals of the traffic light or a controller. If the controller signals contradict traffic signals and indications of road signs, then you need to be guided by the requirements of the regulator.

If traffic lights contradict the requirements of road signs 2.1, 2.4 or 2.5, then you need to be guided by the traffic light.

To enter the adjustable intersection allows the allowing traffic signal or adjustment. Permissive traffic lights are:

It's important to know!
When moving on a prohibitive (crane or yellow) signal with a green additional arrow, the driver must give way to any vehicles moving from other areas.

With the prohibiting signal of the traffic light or a controller, the driver must stop in front of the stop line indicated by markup or sign 6.16, and in their absence - before intersectable passage, without creating pedestrian interference.

Priority movement of trams and firefight vehicles

If the allowing signal is fed simultaneously to tram and straight vehicles, the trams pass the intersection in any direction primarily, and the fine vehicles are in the second.

However, if the tram moves to a prohibitory signal with an additional green arrow, it must give way to the rest of the vehicle, which move to the green light.

Departure from adjustable intersection

Departure from the adjustable intersection is determined by the direction of your further movement. Trams among themselves, and light-speed vehicles - among themselves travel around the following rules:

• the driver moving straight is not inferior to anyone;
• the driver of the tram or a straight vehicle, turning to the right, is inferior to the way only pedestrians and cyclists continuing to move directly;
• the driver turning to the left is inferior to the road to the oncoming vehicles (including performing the right turn), as well as pedestrians continuing to move directly;
• the driver performing the turn is inferior to the road only on the oncoming vehicles.

Driver's actions when switching traffic

Having entered the intersection to the permissive traffic signal (including the flashing green), the driver must release the intersection, even if the traffic light switched to the prohibitive signal, provided that there are no stop lines on the path of its follower.

However, if there is a stop line, after the prohibitive signal has been turned on, the driver is obliged to stop in front of it and resume movement only after the green light turns back.

The same rule needs to be guided at the crossroads with the regulator.

Taking into account the above, at intersections with intensive movement, if necessary, turn left or turn on the green light. The following sequence of actions are recommended:

It's important to know!
Even after switching on the allowance of the traffic light signal, the driver must give way to the road to vehicles ending the movement through the intersection, as well as pedestrians ending the road transition.

Travel Crossroads by adjustrial signals

The adjustment signals can allow you to move in several directions.

At the same time, it is necessary to follow the rules of location on the roadway before turning to the right, left or reversal, as well as take into account the requirements of the signs 5.15.1, 5.15.2 or markup 1.18, indicating the directions of the lanes movement.

4. The movements of two pedestrians are described by the equations x1 \u003d 0.5t and x2 \u003d 5-t. Describe the nature of the movement of each pedestrian, find the module and direction of their speeds, build the charts of movement, speed graphics and determine graphically the place and time of their meeting.

5. The movements of the two bodies are described by the equations x1 \u003d 12-3t and x2 \u003d 2 + 2t. Analytically define the place and time of the meeting.

A. 4M; 2C. B. 2M; 6C. B. 6m; 2c. G.2 m; 4C.

6. The electric trading with a length of 200 m enter the bridge with a length of 500 m, moving uniformly at a speed of 5 m / s. After what time, the train will completely pass the whole bridge?

A. 100 p. B. 40 s. B.140 p. G. 50 s.

Option 1.1.

1.Thevertolet evenly rises vertically upwards. What is the trajectory of the movement of the point at the end of the blade of the screw of the helicopter in the reference system associated with the helicopter housing?

A. Point. B. Direct. B. Circle. Print line.

2. Clear floats along the river. What is the speed of the swimmer relative to the bank of the river, if the speed of the swimmer relative to the water is 1.5 m / s, and the flow rate of the river 0.5 m / s?

3.The remotely floats on the river at a speed of 6 m / s. The person moves across the flesh at a speed of 8 m / s. What is the speed of a person, in the reference system associated with the shore?

A. 2 m / s. B. 7 m / s. B. 10 m / s. G 14 m / s.

V1. Fig. B.

Fig. BUT

A. 1. B. 2. V. 3. G. 4.

5. The boat swims the river with a width of 600 m, and the steering wheel holds the course in such a way that the boat is driving perpendicular to the shores all the time. The speed of the boat relative to the water is 5 m / s, the flow rate of the river 3 m / s. How long does the boat reach the opposite shore?

T e s t № 3 "Speed. The relativity of motion. "

Option 1.2.

1.Thevertolet evenly rises vertically upwards. What is the trajectory of the movement of the point at the end of the blade of the screw of the helicopter in the reference system associated with the helicopter housing?

BUT. . Circle. B. Screw line. V. Point. G. Straight

2. Clear floats along the river. What is the speed of the swimmer relative to the banks of the river, if the speed of the swimmer relative to the water is 1 m / s, and the river flow rate of 0.5 m / s?

A. 0.5 m / s. B. 1 m / s. B. 1.5 m / s. G. 2 m / s.

3.The remotely floats on the river at a speed of 3 m / s. The person moves across the raft at a speed of 4 m / s. What is the human speed in the reference system associated with the shore?

A. 2 m / s. B. 7 m / s. B. 4.6 m / s. G 5 m / s.

4.Con the intersection is approaching truck at a speed v1 \u003d 10m / s and passenger car, at a speed v2 \u003d 20 m / s (Fig. A). What direction has a vector V21 of the velocity of the passenger car in the truck reference system (Fig. B)?

2 Fig. B.

V1. 2 Fig. B.

Fig. BUT

A. 4. B. 3. V. 2. G. 1.

5. The boat swims the river with a width of 800 m, and the steering wheel holds the course in such a way that the boat is floating perpendicular to the shores all the time. The speed of the boat relative to the water is 5 m / s, the flow rate of the river 3 m / s. How long does the boat reach the opposite shore?

A. 120 p. B. 150 s. B. 200 p. G. 90 s.

T e s t № 3 "Speed. The relativity of motion. "

Option 2.1.

A. Point. B. Circle.

B. Direct. Print line.

2. Povers floats against the flow of the river. What is the speed of the swimmer regarding the banks of the river, if the speed of the swimmer is relative to the water

1.5 m / s, and the flow rate of the river 0.5 m / s?

3. Kran evenly raises the load vertically up at a speed of 0.3 m / s and at the same time evenly and straightly moving along the horizontal rail
Speed \u200b\u200bwith a speed of 0.4 m / s. What is the speed of cargo in the earth-related reference system?

A. 0.1 m / s. B. 0.35 m / s. B. 0.5 m / s. 0.7 m / s.

Fig. B.

1 4

Fig. BUT

À. 1. B.2. IN 3. G.4.

5. The speed of the boat movement flooding over the coast is equal to 3m / s, and the speed of the same boat floating against the flow is 2 m / s. What is the flow rate?

T e s t № 3 "Speed. The relativity of motion. "

Option2.2

1.Thevertolet evenly rises vertically upwards. What is the trajectory of the movement of the point at the end of the blade of the helicopter screw in the reference system associated with the surface of the Earth?

A. Point. B. Straight.

B. Screw line. Circle.

2. Povers floats against the flow of the river. What is the speed of the swimmer relative to the banks of the river, if the speed of the swimmer relative to the water is 1 m / s, and the river flow rate of 0.5 m / s?

À. 0.5 m / s. B. 1m / s. B. 1.5 m / s. G. 2 m / s.

3. Cranp evenly raises the load vertically up at a speed of 0.3 m / s and at the same time evenly and straightly moving along horizontal rails at a speed of 0.4 m / s. What is the speed of cargo in the earth-related reference system?

A. 0.35 m / s. B. 0.1 m / s. B. 0.7 m / s. 0.5 m / s.

4. The rain, flying with a constant speed, V vertically down, falls on the vertical surface of the glass of the wagon moving at a constant speed U (Fig. A). Which of the trajectories in the picture B corresponds to the drop drop on the glass?

Fig. B.

4 3

Fig. And fig. B.

À. 1. B.2. IN 3. G.4.

5. The speed of the engine boat flowing downstream relative to the shore is equal to 4m / s, and the speed of the same boat floating against the flow is 2 m / s. What is the flow rate?

A. 0.5 m / s. B.1m / s. B.1.5 m / s. G.2,5m / s.

Option 1.1.

IN .A \u003d 0.

The direction can be anyone.

2. According to the chart of the dependence of the module V , m / s

speed \u200b\u200bof time represented
in the picture, determine the acceleration
straightly moving body at the moment
of time t.= 2c.

A. 2 m / s2 V. 9 m / s2.

B. 3 m / s2. G. 27 m / s.2

3. Under the condition of task number 2, determine the movement of the body in three seconds.

A. 9 m. B. 18m. B.27M. G. 36 m.

4. A car after 100m after the start of the movement acquires the speed of 30m / s. What acceleration was moving a car.

A. 4.5 m / s2. B. 0.15 m / s2. B. 9.2 m / s2. G. 11m / C2.

V. x. = 2 + 3 t.

A. SX. = 2 t. + 3 t.2 (m). IN. SX. = 2 t.+ 1,5T2 (M).

B. SX. = 1,5T2 (M). G. SX. = 3 t. + t.2 (m)

5 m / s. Under the action of friction forces, the bar is moving with an acceleration of 1 m / s2. What is the path passed by Bruk for 6 s?

Test №4 "Equal asked straight movement".

Option 1.2.

1. Suggestion and acceleration of the body moving straightforwardly and equally discharged, shown in the figure. What is this movement?

V. but H.

A. rests. B. Moves equally.

B. Moves. evenly. G. Moves Equally.

2. According to the velocity module dependence

from the time shown in Figure V , m / s

Determine the acceleration straight-line 80

moving body at time

t.= 20c. 40.

A. 2 m / s2 V. 9 m / s2.

B. 3 m / s2. G. 27 m / s.t, with

3. Under the condition of task number 2, determine the movement of the body for t.= 20c.

A. 820m. B. 840m. B.1000m. G. 1200m.

4. What acceleration fell a stone, if for 2s them passed 19.6m?

A. 19.6 m / c2. B. 9.8 m / s2. B. 9 m / s2. G. 15.68m / C2.

x. = 2 - 3 t. (m / s). What is the corresponding equation of the projection of the body movement?

A. SX. = 2 t. - 3 t.2 (m). IN. SX. = - 1,5T2 (M).

B. SX. = 2 t.- 1,5T2 (m). G. SX. =2 t. +1,5 t.2 (m).

6. Bruck reported on the horizontal surface of the table, 5 m / s. Under the action of the forces of thrust bar moves with an acceleration of 1 m / s2. What is the path passed by Bruk for 6 s?

A. 6 m. B. 12 m. V. 48m. G. 30 m.

Test №4 "Equal asked straight movement".

Option 2.1.

1. The body of the body moving straight and evenly zealously changed when moving from point 1 to point 2, as shown in the figure. What direction has the spelling vector on this site?

IN. A \u003d 0.

B. a \u003d 0.

Maybe anyone.

2. According to the chart of dependence V , m / s

presented in Figure 10

determine Acceleration 5.

at the time of time t.=1 from.

A. 2 m / s2 V. 5 m / s2.

B. 3 m / s2. G. 7.5 m / s, with

4. Car moving with 2m / s acceleration 2 , passes 100m. What speed does it come in?

A. 40 m / s. B. 100 m / s. B. 80 m / s. G. 20m / s.

5. Equation of the dependence of the projection of the speed of a moving body from time: v x. = 3 + 2t. (m / s). What is the corresponding equation of the projection of the body movement?

A. SX. = 3 t.2 (m). IN. SX. = 3 t.+ 2 t2 (m).

B. SX. = 2 t.+ 3 t2 (m). G. SX. = 3 t. + t.2 (m).

6. Bruck was reported on the horizontal surface of the table, the velocity of 4 m / s. Under the action of friction forces, the bar moves with an acceleration of 1M / C2. What is the path passed by Bruk for 4 s?

A. 8M. B.12m. B. 28m. G. 30m.

Test # 4 "Equal asked rectilinear movement".

Option 2.2

1. The sound and acceleration of the body moving straightly shown in the figure. What is this movement?

A. Uniform. B. Equal asked.

V. Equalized. G. Pochka.

2.Abe the graph of V dependence V , m / s

Presented in Figure 20

determine Acceleration 10.

straight-moving body 0

at the time of time t.=2 cT, S.

A. 2 m / s2 V. 10 m / s2.

B. 3 m / s2. G. 5 m / s.2

3. Under the condition of task number 2, determine the movement of the body in two seconds.

A. 5 m. B. 10m. B.20m. G. 30 m.

4. What's the way conducted a car Moving with acceleration 2m / s 2 if the end acquires the speed of 72km / h?

A. 40 m. B. 100 m. V. 80 m. G. 20m.

5. Equation of the dependence of the projection of the speed of a moving body from time to time:

V. x. = 3 - 2t. (m / s). What is the corresponding equation of the projection of the body movement?

A. SX. = 3 t.2 (m). IN. SX. = 3 t.- T2 (m).

B. SX. = 2 t.+ 3 t2 (m). G. SX. = 3 t. + t.2 (m).

6. Bruck reported on the horizontal surface of the table.

4 m / s. Under the action of the forces of thrust bar moves with an acceleration of 1M / C2. What is the path passed by Bruk for 4 s?

A. 6 m. B. 12 m. V. 24m. G. 30 m.

Test No. 5 "Free Fall".

Option 1.1.

1. In the tube, from which the air is dumped, on the same height, there are crushers, traffic jams and bird feather. Which of these bodies will reach the bottom of the tube?

2. What is the speed of a free incident body after 4 seconds?

A. 20 m / s. B. 40 m / s. B. 80 m / s. G. 160 m / s.

3. How will the path go through a freely falling body for 3 seconds?

A. 15 m. B. 30 m. V. 45m. G. 90 m.

4. What path will pass freely falling body over the fifth second?

A. 45 m. B. 50 m. V. 125 m. 250 m.

5. The body is thrown up vertically up at a speed of 30 m / s. What is equal to maximum height lifting?

A. 22.5 m. B. 45 m. V. 90 m. 180 m.

Test No. 5 "Free Fall".

Option 1.2.

Acceleration of free fall Please accept 10 m / s2.

1.To moves vertically up at V. How to accelerate

free fall, and what kind of point is subject to this movement?

2.What is the speed of a free incident body after 10 seconds?

A. 20 m / s. B. 40 m / s. B. 80 m / s. G. 100 m / s.

3. How will the path go through a freely falling body for 5 seconds?

A. 25 m. B. 30 m. V. 50m. 125 m.

4. How will the path pass a freely falling body over the tenth second?

A. 45 m. B. 50 m. V. 95 m. G. 100 m.

5.Tello thrown up vertically at a speed of 50 m / s. What is the maximum equal to

lift height?

A. 2 m. B. 20 m. V. 100 m. G. 125 m.

Test No. 5 "Free Fall".

Option 2.1

Acceleration of free fall Please accept 10 m / s2.

1. In the tube, from which the air is dumped, on the same height, there are crushers, traffic jams and bird feather. Which of these bodies will later reach the bottom of the tube?

A. Crushing. B. Cork. B. Bird Feather.

G. All three bodies reached the bottom of the tube at the same time.

2.What is the speed of a free incident body after 3 seconds?

3. How will the path go through a freely falling body in 4 seconds?

4. How will the way go through a freely falling body for the sixth second?

A. 55 m. B. 60 m. V. 180 m. 360 m.

5.Tello thrown up vertically up at a speed of 20 m / s. What is the maximum lifting height?

A. 10 m. B. 20 m. V. 100 m. 80 m.

Test No. 5 "Free Fall".

Option 2.2.

Acceleration of free fall Please accept 10 m / s2.

1.To moves vertically down at V. How to accelerate free fall, and what kind of point is subject to this movement?

A. Up, equatively. B. Down, equatively.

V. Up is equivalent. G. down equivalent.

2. What is the speed of a free falling body after 9 seconds?

v.0 \u003d 0m / s, Acceleration of the free fall Please take 10 m / s2.

A. 15 m / s. B. 30 m / s. B. 45 M / s. G. 90 m / s.

3. How will the path go through a freely falling body for 2 seconds? v.0 \u003d 0 m / s, Accelerating the free incidence. Take equal to 10 m / s2.

A. 20 m. B. 40m. V.80m. G.160 m.

4. How will the way go through a freely falling body for the second second?

v.0 = 0 m / s, acceleration of free fall Please take 10 m / s2.

A. 5 m. B. 15 m. B. 18 m. 36 m.

5. With what speed body throws up vertically, if the maximum lift height is 20m? Acceleration of free fall Please accept 10 m / s2.

A. 10 m. B. 20 m. B. 40 m. 80 m.

Option 1.1.

direction clockwise. how

the speed of acceleration is directed, with this 1

movement?

2. The car moves on a turn around the circular trajectory with a radius of 50 m with a constant modulo by a speed of 10 m / s. What is the acceleration of the car?

A. 1 m / s2. B. 5 m / s2.

B. 2 m / s2. G. 0 m / s2.

3. The body moves around the circle with a radius of 10 m. The period of its appeal is 20c. What is the body speed?

A. 2 m / s. B. 2 π m / s.

B. π m / s. G. 4 π m / s.

4. The body moves around the circumference with a radius of 5 m at a speed of 20 π m / s. What is the frequency of circulation?

A. 2 C - 1. V. 2 π 2 s -1.

B. 2 π s -1. 0.5 s -1.

R.1 = R. and R.2 = 2 R. from

same speeds. Compare their centripetal acceleration.

A. 1 m / s2. B. 5 m / s2.

B. 2 m / s2. G. 0 m / s2.

3. The body moves around the circle with a radius of 20 m. The period of its appeal is 20c. What is the body speed?

A. 2 m / s. B. 2 π m / s.

B. π m / s. G. 4 π m / s.

4. The body moves around the circumference with a radius of 2m at a speed of 20 π m / s. What is the frequency of circulation?

A. 2 C-1. B. 2 π 2 s-1

B. 2 π C-1. G. 5 C-1.

5. Two material points are moving around the circles of radius R.1 = R. and R.2 = 2 R. from

identical angular speeds. Compare their centripetal acceleration.

BUT. a1 \u003d. a2.B. a1 \u003d. 2a2.IN. A1.= but2/ 2 g A1 \u003d. 4a2.

Test No. 6 "Movement around the circle".

Option 2.1

1.Tello moves uniformly around the circumference in 2

direction counterclockwise. how

Option 1.1 1.Tright rises evenly upright up. What is the trajectory of the movement of the point at the end of the blade of the helicopter screw in the system commercially associated with the helicopter housing? A. Point. B. Direct. B. Circle. Print line. 2. Clear floats along the river. What is equal to the speed of the swimmer relative to the banks of the river, if the swimmer speed relative to the water is 1.5 m / s, and the river flow rate of 0.5 m / s? A. 0.5 m / s. B. 1 m / s. B. 1.5 m / s. G. 2 m / s. 3.The remotely floats on the river at a speed of 6 m / s. A person moves across the flesh with a speed of 8 m / s. What is the speed of a person, in the reference system associated with the shore? A. 2 m / s. B. 7 m / s. B. 10 m / s. G 14 m / s. 4.Co the intersection is approaching the cargo machine at a speed V 1 \u003d
V 1. Fig. B.
Fig. BUT A. 1. B. 2. V. 3.. The speed of the boat relative to the water is 5 m / s, the flow rate of the river 3 m / s. How long will Lod-ka reach the opposite shore? A. 120 p. B. 150 p. B. 200 p. G. 90 s. T e s t № 3 "Speed. The relativity of motion. " Option 1.2 1.Tright evenly rises vertically upwards. What is the trajectory of the movement of the point at the end of the blade of the helicopter screw in the system commercially associated with the helicopter housing? BUT. . Circle. B. Screw line. V. Point. G. Straight 2. Clear floats by the flow of the river. What is equal to the speed of the swimmer relative to the banks of the river, if the speed of the swimmer relative to the water is 1 m / s, and the river flow rate of 0.5 m / s? A. 0.5 m / s. B. 1 m / s. B. 1.5 m / s. G. 2 m / s. 3.The remotely floats on the river at a speed of 3 m / s. The person moves across the flesh with a speed of 4 m / s. What is the human speed in the reference system associated with the shore? A. 2 m / s. B. 7 m / s. B. 4.6 m / s. G 5 m / s. 4.Co the intersection is approaching the cargo machine at a speed V 1 \u003d 10m / s and a light machine, with a velocity V 2 \u003d 20 m / s (Fig. A). What direction has a vector V 21 of the speed of passenger machine in the truck reference system (Fig. B)? 2 Fig. B. V 1. 2 Fig. B.Fig. BUT A. 4. B. 3. V. 2. G. 1.
5. The boat swims the river with a width of 800 m, and the steering wheel holds the course in such a way that the boat is floating perpendicular to the shores all the time. The speed of the boat relative to the water is 5 m / s, the flow rate of the river 3 m / s. How long will Lod-ka reach the opposite shore? A. 120 p. B. 150 s. B. 200 p. G. 90 s. T e s t № 3 "Speed. The relativity of motion. " Option 2.1 1.Tright evenly rises vertically upwards. What is the trajectory of the movement of the point at the end of the blade of the helicopter screw in the system commercially associated with the surface of the earth? A. Point. B. Circle. B. Direct. Print line. 2. Povers floats against the flow of the river. What is the speed of the swimmer relative to the bank of the river, if the speed of the swimmer relative to the water is 1.5 m / s, and the flow rate of the river 0.5 m / s? À. 0.5 m / s. B. 1m / s. B. 1.5 m / s. G. 2 m / s. 3. Cranp evenly raises the load vertically up at a speed of 0.3 m / s and at the same time evenly and straightly moving along the horizontal rail--
speed \u200b\u200bwith a speed of 0.4 m / s. What is the speed of cargo in the earth-related reference system? A. 0.1 m / s. B. 0.35 m / s. B. 0.5 m / s. 0.7 m / s. 4. Cape of rain, flying with a constant speed, V vertically down, falls on the vertical surface of the glass of the car moving at a constant speed U Fig. B. 2 3Fig. BUT À. 1. B.2. IN 3. G.4. 5. The speed of the boat movement flooding over the coast is equal to 3m / s, and the speed of the same boat floating against the flow is 2 m / s. What is the flow rate? A. 0.5m / s. B.1m / s. B.1.5 m / s. G.2,5m / s. T e s t № 3 "Speed. The relativity of motion. " Option2.2 1. Thevertolet evenly rises vertically upwards. What is the trajectory of the movement of the point at the end of the blade of the helicopter screw in the system commercially associated with the surface of the earth? A. Point. B. Straight. B. Screw line. Circle. 2. Povers floats against the flow of the river. What is the speed of the swimmer relative to the banks of the river, if the speed of the swimmer relative to the water is 1 m / s, and the river flow rate of 0.5 m / s? À. 0.5 m / s. B. 1m / s. B. 1.5 m / s. G. 2 m / s. 3. Cranp evenly raises the load vertically up at a speed of 0.3 m / s and at the same time evenly and straightly moving along horizontal rails at a speed of 0.4 m / s. What is the speed of cargo in the earth-related reference system? A. 0.35 m / s. B. 0.1 m / s. B. 0.7 m / s. 0.5 m / s. 4. Cape of rain, flying with a constant speed, V vertically down, falls on the vertical surface of the glass of the car moving at a constant speed U (Fig. A). Which of the trajectories in the picture B corresponds to the drop drop on the glass? Fig. B. 1 2Fig. BUT Fig. B. À. 1. B.2. IN 3. G.4. 5. The speed of the engine boat flowing downstream relative to the shore is equal to 4m / s, and the speed of the same boat floating against the flow is 2 m / s. What is the flow rate? A. 0.5m / s. B.1m / s. B.1.5 m / s. G.2,5m / s. Test №4 "Equal asked straight movement".Option 1.1. 1. The body of the body moving straight and evenly zealously changed when moving from point 1 to point 2, as shown in the figure. What direction has the spelling vector on this site? V 1 V 2 x.
A. B .. IN .A \u003d 0. The direction can be anyone. 2. . On the module's dependence schedule V , m / s Speed \u200b\u200bof time represented
in the picture, determine the acceleration
straightly moving body at the moment
of time t.= 2c. A. 2 m / s 2 V. 9 m / s 2. B. 3 m / s 2. G. 27 m / s. 2 3. Under the condition of task number 2, determine the movement of the body in three seconds. A. 9 m. B. 18m. B.27M. G. 36 m. 4. The car after 100m after the start of the movement acquires the speed of 30m / s. What acceleration was moving a car. A. 4.5 m / s 2. B. 0.15 m / s 2. B. 9.2 m / s 2. G. 11M / C 2. 5. Equation of the dependence of the projection of the speed-caught body from time: v x. = 2 + 3 t. (m / s). What is the corresponding Body Projection Projection Equation? A. S. x. = 2 t. + 3 t. 2 (m). IN. S. x. = 2 t.+ 1.5T 2 (M). B. S. x. = 1.5T 2 (M). G. S. x. = 3 t. + t. 2 . According to the chart of the QU speed module x. = 2 t. - 3 t. 2 (m). IN. S. x. = - 1.5T 2 (M). B. S. x. = 2 t.- 1.5T 2 (M). G. S. x. =2 t. +1,5 t. 2 (m). 6. Bruck reported on the horizontal surface of the table, 5 m / s. Under the action of the thrust forces, the bar is moving with an acceleration of 1 m / s 2. What is the path passed by the Barrier for 6 s? A. 6 m. B. 12 m. V. 48m. G. 30 m.

In this article, we will analyze the rules for the passage of unregulated intersections of equivalent and unequivocal roads. Consider on the example of the simplest intersection with the intersection of two passages. Realizing and remembering how to pass such a crossroads, you can easily understand in more complex intersections.

Handing to the unregulated crossroads, it is necessary to look at the priority signs and determine who needs to give way to the road. At such a crossroads, we can go in four directions, namely: to the right, right, left and in the opposite direction. Other participants in the movement approach us from three directions: on the left (blue car), right (black) and from the oncoming direction (green).

When considering the situations depicted in the figures, we will assume that all cars move in the same direction as we. Those. If we turn to the intersection to the right, then the blue car goes straight, green turns left, black unfolds. Also on the other directions of our movement, we will always have the intersection points of the trajectories with all cars.

Before the intersection is the sign "Main Road"

When we go along the main road, you will have to give way to the road only cars that are also moving along the main road and will approach us on the right side.

1. When turning right to the right, no one is inferior to the road.
2. When moving, it is also not inferior to anyone.
3. When turning to the left and turn, we give the way to the oncoming vehicles (green vehicle), moving in our direction (in this case, I am moving until the middle of the crossroads and wait until they go), since they are also on the main road and are no interference on right. If the oncoming turns left, then traveling with them with right sides.

The main road turns to the left

Sign "Main Road" together with the sign "Direction of the main road".

1. When turning right, we pass the intersection first.
2. Also when driving a crossroads in the forward direction.
3. No one is inferior when turning to the left.
4. And only when reversing, you will have to give way to the TC on the left (the blue car turns to the right), because they are also going along the main one and will be a hindrance to us right.

If the blue car goes straight, then at first we will have a hindrance to him (i.e. we have an advantage), but by reaching the middle of the crossroads and turning around in the opposite direction, they already have the right side of him and will have to give up.

At narrow intersections, it will be difficult to disperse in this way, so it is advisable to cede its advantage to blue and perform the maneuver, after it goes straight.

The main road turns right

1. If you plan to go to the right, we can safely pass first, because this is the only direction, when moving in which no one needs to be given.
2. When you go directly do not forget to see the right and give way to a black car, which is also moving along the main road and approaching our right.
3. Moving to the left, also you will also have to give up the vehicle on the right, which are directly direct or rotated to the left. If a black car turns to the right, then we will not create it no interference and can perform a turn simultaneously with it. Just need to make sure that he really began to perform a turn, but maybe it will drive directly with the turned on the turn signal.
4. Deploying, act as well as when turning to the left.

Before the intersection is installed sign "Landing the road"

When driving a crossroads give way to everyone who rides on the main road, as well as those who are with secondarynext to us on the right. Landing the road, stop at the intersection of passages.

1. When turning right to give way to the road to the left (blue car), since they are moving along the main road. If the blue car has turned on the right direction indicator and began to turn, then you can pass at the same time with it. In the case when the black car (right) decides to turn on the crossroads, you will have to give way to the road and to him.
2. By performing the passage of unregulated intersections in the forward direction, we give way to cars on the left (blue) and right (black).
3. When turning to the left, besides, it is necessary to give way to cars to the left and right, you will have to skip and counter TCs, which, like we are on a secondary road, will be "hindrance to us."
4. If you decide to take a turn at the crossroads, you will also have to give way to all vehicles.

Main road left

1. When turning right, we give up the TC on the left (blue car) and the oncoming (green), if they go there and we are.
2. Moving in the forward direction, it is necessary to give way to the left, counter, because they are going along the main road, as well as on the right (black car) although they are also secondary, but are "hindrance to the right."
3. When turning to the left is also inferior to everyone.
4. Not very the best way For reversal, but if there is no choice, we perform, yielding to all vehicles.

Home Road Right

1. Before turning to the right, you should make sure that no one goes from the counter direction in our direction, and also that a black car (right) is not going to turn on the intersection.
2. Moving directly or left, we will also give up the road to green and black cars, since they go along the main road.
3. When turning at the crossroads will have to give both a blue car, because by performing this maneuver, we turn to it right side. But at the same time, approaching the intersection of the passage parts themselves will be "hindrance to the right" and therefore have an advantage.

Rules of travel unregulated intersections of equivalent roads

Following the crossroads of equivalent roads, guided p.13.11 rules road. We give way to cars approaching the right.

1. When turning right, we do not need to give way to anyone.
2. Driving crossroads in straight direction, give way to the right (black car). In the case when black, green and blue cars are also going straight, drivers will have to decide who will go first, because the rules of this situation are not regulated.
3. When turning to the left for us and black and green cars There will be a hindrance to the right.
4. When performing the reversal, you will have to give up all three directions. At the same time, the blue will have an advantage only when we will go in the opposite direction from the middle of the intersection.

Generalize the rules for the pass of unregulated intersections

1. At the intersection of equivalent roads, we look at who we will approach the right.
2. If you are installed by the "LDA" sign, we skip those who are going on the main one, then those who are at the secondary approach to us right.
3. The "Main Road" sign - we give only those who, too, at the main approaching to our right.